How to process the received View in js?

Question

JavaScript

function A() {
              
                    $.get("/Home/B", {
                        "Email": document.getElementById("Email").value,
                        "Password": document.getElementById("Pass").value   },
                     function (data) {
                     //  ......
                     });

[HttpGet]
        public ActionResult B(string Email, string Password)
        {
           //some code

            return View();
        }

The request is sent and executed successfully. The controller returns a view. How in the success get function of the request, accept and display the received View?

Answer 1

Try it, maybe your solution
Make some empty block on the page where you plan to insert
In success, if you get ready html write it like this

success :  function (data) {
                     $('div#input_ajax').html(data)
                     })