How to parse URL inside script in python?

Question

Python

I'm trying to get pictures from this page , I use session.get, I see the following:

It doesn't seem to matter, the code contains links to all the highres, but all but the first one are inside the script, and the script itself looks like this: The

necessary links, respectively, lie far inside this line.
Now I use soup.find_all('script'), among the output I find the script I need, so now I have two questions, how to find only one script and not all at once, and are there any ways to pull URLs out of a huge string other than using scary regulars?

Answer 1

I remember I gave the code in the last answer .
https://www.artstation.com/projects/o1eqm.json
This link has it all.

Answer 2

It's not easier to look for something like " https://cdna.artstation.com/p/assets/images/images/ " - start, ".jpg" - end.
You don't need any scary regular expressions
All the pictures on these links and pull out