How to parse generated link in Python?

Question

Python

Such question:
I write a parser for a site. At one point, where you need to take a link for further access, it is encapsulated and html does not see it. Those. for the user it is, but the parser sees not the link, but the js that generates it.
The link itself: https://examples/chats/view?chat_id=56399666&type=...
And the code that generates it and which the parser sees:

var transfer = (aData[9]) ? 'class="icon arrow-circle" title="'+'Принят от '+aData[9]+'"' : '';
                $('td:eq(6)', nRow).html('<span '+transfer+'>' + aData[6] + '</span>').find('.arrow-circle').tooltip();
                $('td:eq(7)', nRow).addClass('action');
                var link = (aData[8] == 'offline') ? 'offline_id' : 'chat_id';
               <b> link = '/chats/view?'+link+'='+aData[0]+'&type='+$type.val()+'&rating='+$rating.val()+
                                                '&period='+$period.val()+'&back='+backUrl;</b>
                if ($period.val() == 'other') {
                    link += '&from='+$("#dateFrom").val()+'&to='+$("#dateTo").val();
                }

                var removeLink = (aData[8] == 'offline') ? 'offline_id' : 'chat_id';
                removeLink = '/chats/remove?'+removeLink+'='+aData[0];
                $('td:eq(7)', nRow).html('<ul class="list-inline menu">' +
                   <b> '<li><a href="'+link+'" id="see" class="icon eye">Просмотр</a></li>'+</b>
                    '<li><a href="'+removeLink+'" id="remove" class="icon close-icon">Удалить</a></li></ul>');

                return nRow;

<b> '<li><a href="'+link+'" id="see" class="icon eye">Просмотр</a></li>'+</b>

- here is the link
Do not tell me, mb somehow it can be pulled out? Using requests and BeautifulSoup

Answer 1

I somehow already answered a similar question, in my opinion this approach is easier and cheaper than bothering with selenium/pyv8/phantomjs/etc

Answer 2

What does the JS code do? There is an option - to port it to Python. Then the link will be generated directly from you.

Answer 3

Perhaps something phantomjs.org will help