How to output only the first line in php foreach?

Question

PHP

I have a php code that pulls all links to images from the page:

<?php
$content = file_get_contents('http://site.ru');
preg_match_all('/<img[^>]+src="?\'?([^"\']+)"?\'?[^>]*>/i', $content, $images, PREG_SET_ORDER);
foreach ($images as $image) {
    echo $image[1] . '<br>';
}
?>

Here is an example: c11634.shared.hc.ru/cmxrd4.php
How to make the page display only the first line? Those. only the first image, the rest are not needed.

Answer 1

In this case it is possible to do without foreach?
echo $images[0][1]. '<br>';

Answer 2

if (isset($images[0])) {
echo $images[0] . '<br>';
}

Answer 3

If it is critical for you to save your code, then just do this:

<?php
$content = file_get_contents('http://site.ru');
preg_match_all('/<img[^>]+src="?\'?([^"\']+)"?\'?[^>]*>/i', $content, $images, PREG_SET_ORDER);
foreach ($images as $image) {
    echo $image[1] . '<br>';
    break;
}
?>

Answer 4

$first_item = array_shift($list);
Correct, because regardless of the index of the first element of the array (there may not be a zero element, for example, as a result of its intentional removal).