How to open a form on click on a row in DataGrid?

Question

WPF

I don't really understand how to track a click on the DataGrid. here is the xaml markup:

<DataGrid AutoGenerateColumns="False" x:Name="dg_recipes" Margin="10,249,10,10">
            <DataGrid.Columns>
                <DataGridTextColumn Header="Название" Binding="{Binding Path='name'}" Width="320"/>
                <DataGridTextColumn Header="Время приготовления" Width="280"/>
            </DataGrid.Columns>
        </DataGrid>

By clicking on the selected line in 1 column, a form should open

Answer 1

• We create a column, the content in the cells of which will represent a Button with the Button_Click event.
  

  <DataGrid Name="MyDataGrid" ItemsSource="{Binding Table}">
      <DataGrid.Columns>
          <DataGridTemplateColumn>
              <DataGridTemplateColumn.CellTemplate>
                  <DataTemplate>
                      <Button Click="Button_Click">Open Form</Button>
                  </DataTemplate>
              </DataGridTemplateColumn.CellTemplate>
          </DataGridTemplateColumn>
      </DataGrid.Columns>
  </DataGrid>

  
  
• Let there be some form TosterForm, the constructor of which takes one string argument - the value in the 3rd column of the selected line.
  

  private void Button_Click(object sender, RoutedEventArgs e)
  {
      TosterForm form = new TosterForm(((DataRowView)MyDataGrid.SelectedItem).Row.ItemArray[3].ToString());
      form.ShowDialog();
  }

  
  Regarding getting the value in the cell, there may be another option, I had practically never worked with the DataGrid before.
  Actually, like everything.