How to make a django form field "disabled" directly in the template?

Question

Django

Dobrechka, gentlemen.
The task is as follows: it is necessary, depending on the presence / non-availability of a certain right for the user, to show him active / inactive fields.
Tell me, can I make the form field "disabled" on the run, in the template?

<div class="col-md-12">
   {% if perms.foo.change_datasettings %}
      {% for field in setting_form %}
          {{ field.label_tag }} {{ field }}
      {% endfor %}
   {% else %}
      {% for field in form %}
          {{ field.label_tag }} {{ field.disabled }}
      {% endfor %}
{% endif %}
</div>

Thank you.

Answer 1

I use widget-tweaks ( https://pypi.python.org/pypi/django-widget-tweaks)
Look at the attr template tag there. They can set any field attribute

Answer 2

This can be done in a form. And even then, the logic itself should be written in view. First, pass an argument to the form that specifies whether to make the fields disabled. And then, already in the form, put down the attributes of the fields.

class MyView(...):
    form_class = MyForm

    def get_form_kwargs(self, ...):   # название метода условно, не уверен, что он так называется в generic views и даже что он есть :)
        kwargs = super(MyView, self).get_form_kwargs(...)
        kwargs.update({'disabled': not self.request.user.has_perm(...)})
        return kwargs

class MyForm(...):
    def __init__(self, *args, **kwargs):
        is_disabled = kwargs.pop('disabled')
        super(MyForm, self).__init__(*args, **kwargs)

        if is_disabled:
            self.fields['foo'].widget.attrs.update({'disabled': 'disabled'})