How to leave a link without additional attributes?

Question

WordPress

Such a question, is it possible to display only the slug / label for posts, headings, pages?

The bottom line is that I need to clear all https and leave only the last name, i.e. https://test.ru/category/admin/test - so that only test remains. I'm doing a kind of data-slug.
And I use it in a function and I need it only for one purpose - in html to have one word "test" at the output.

I tried to use str_replace, preg_replace, but with the taxonomy of headings in the output, there are only more of them in http.

What is it for? - The bottom line is the front, because it is built from blocks and they can be "glued" on js, thus I will get the possibility of a multi-level menu with sliders, etc., etc.

Answer 1

Thanks everyone, I did it myself.
I made an array from the transliteration and translated all the titles and got the titles of all the records, etc., etc.

Answer 2

You can get the slug like this:

$post_slug = get_post_field( 'post_name', get_post() );

You can pass the entire object or just the record id to the function. If you only have a link, use a regular expression

$link = 'https://test.ru/category/admin/test';

$regexp = "/\/(?<slug>[^\/]+)[\/]?$/";
$reglink = preg_match( $regexp, $link, $match_link );
$slug = $match_link['slug'];

var_dump( $slug );