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How to learn the checksum algorithm without many examples?
Hello, there are several codes of this format. By a
475314 / 2021
simple observation, I realized that the last digit (4) is the digit to check.
The documents issued in a row differed by the penultimate digit +1
. If 20 (21) is added in front of the code and the EAN-8 algorithm is used, then the code is sometimes (mostly) converge cases, and if not, then simply increase 21 by 22 or 22 by 23 and it works. But I would like to be sure, because it concerns that this is just an accident
* I have ± 5 examples of such codes (
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In general, no way. We need as many examples as possible. There you can already speculate on some of them and check on the rest. 5 examples is probably not enough. There is a possibility that there is something standard. Then you need to go through the algorithms until it converges on all examples, but even here there may be a possibility of an error - it’s just that several algorithms work on your examples and you chose the wrong one that actually exists.
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