How to know the output of a debug smtp server in Python?

Question

Python

The bottom line is this: there is a script that sends a letter through smtplib, which is configured for localhost and port 1025. The python debug server is running at the same address and port. The question is how to get the output of this server from the script? In words, it may not be clear, here are code snippets:

import subprocess
import shlex

command = 'python -m smtpd -n -c Debugging Server localhost:1025'
args = shlex.split(command)
p = subprocess.call(args, stdout=open('temp.txt', 'w'))
#здесь функция, которая отправляет почту через smplib.SMTP('localhost', 1025)
p.kill()

Accordingly, the temp.txt file is empty, although if you start the server through the terminal, the mail goes through and the message is displayed.
Along the way, a parallel question: is there any other way to debug on a local server without using non-standard modules?

Answer 1

What a horror.
Why do you need a separate server to send one message?
Why didn't you want to connect to a real server?

Answer 2

Try testing SMTP with the free debugmail service .