How to know if an array value is equal to a given number?

Question

PHP

Hello!
There is an array like:

Array
(
    [0] => Array
        (
            [status] => 
            [user_id] => 39828
            [birthday] => 0
            [gender] => 1
        )

    [1] => Array
        (
            [status] => 
            [user_id] => 39827
            [birthday] => 0
            [gender] => 1
        )

    [2] => Array
        (
            [status] => 
            [user_id] => 38497
            [birthday] => 22
            [gender] => 1
        )

    [3] => Array
        (
            [status] => 
            [user_id] => 37043
            [birthday] => 29
            [gender] => 1
        )

)

I need to find out without using cycles whether there is an array with the element [user_id] === 37043 (for example), and if so, delete it.
I tried array_map(), but it takes an array as the last argument, and I only need to pass 37043.
Any ideas?

Answer 1

Returns found occurrences

$user_id = 37043;

$res = array_filter($your_array, function($arr) use ($user_id){
     return ($arr['user_id'] == $user_id);
});

Otherwise returns an empty array
Function reference - php.net/manual/en/function.array-filter.php

Answer 2

Why don't you like the cycle?

Answer 3

I think the array_filter method will suit you ( nl3.php.net/manual/en/function.array-filter.php )
That is, you get something like:

$result= array_filter($array, function($var){
return $var['user_id'] == <искомое_значение>
})

I can't vouch for the correctness of the code. Haven't written in PHP for 100,500 years. In JavaScript, this method works like this)