How to implement and pass a dynamic filename to a variable or directly?

Question

Python

There is a password generator. Below is the part that creates the file and puts the passwords in it. It is required to pass the created file to the record construction. But, because the file is created with datetime.now() , it can't be explicitly tracked and passed for writing.
Sorry for the inexperience. *** Newbie... what can I say ***
I would be grateful for your help)

os.mknod("passwords " + str(datetime.datetime.now().time()) + " .txt")

with open('passwords *** .txt', 'w') as f:
    for item in passHistory:
        f.write("%s\n" % item)

sizeFile = os.path.getsize('passwords.txt')

Answer 1

name = str(datetime.datetime.now().time())
os.mknod("passwords " + name + " .txt")

with open('passwords '+name+' .txt', 'w') as f:
    for item in passHistory:
        f.write("%s\n" % item)

sizeFile = os.path.getsize('passwords '+name+' .txt')