How to handle change event on esp8266 GPIO?

Question

IDE

There is esp2688. It seems like a simple task, without using an arduino. Only esp 2688.
You need to send request A when receiving a pulse on gpio0. those. momentary level change to gpio0.
and request B when receiving a pulse on gpio1 on gpio1.
And then wait for the next. either of the two impulses.
Actually, as far as I understood the so-called. there are no interrupts in esp 2688.
maybe some kind of tricky move will help?
PS impulse from water sensors.

Answer 1

Using nodemcu:
In fact, this is the processing of a button press, already with bounce protection.

local pin = 4    --> GPIO2

function debounce (func)
    local last = 0
    local delay = 200000

    return function (...)
        local now = tmr.now()
        if now - last < delay then return end

        last = now
        return func(...)
    end
end

function onChange ()
    print('The pin value has changed to '..gpio.read(pin))
end

Solution found.

Answer 2

Actually, as far as I understood the so-called. there are no interrupts in esp 2688.

I wonder how you figured it out?
Section 7.1 of document 2C-ESP8266__SDK__Programming Guide__EN_v1.2.0.pdf describes the functions for working with GPIO, among which are ETS_GPIO_INTR_ATTACH, ETS_GPIO_INTR_ENABLE and gpio_pin_intr_state_set.
Don't forget to also set up PINMUX before using the GPIO.