How to get the value for the fields from the server?

1

1bubaleh2016-08-05 21:37:22

PHP

1bubaleh, 2016-08-05 21:37:22

Good evening, comrades!
Using the "Submit" button sent the form data to the server.
But how to make it so that when you click on the "Add field" button, the fields contain values that have already been sent?

<!DOCTYPE html>
<html>
 <head>
   <title>!DOCTYPE</title>
   <meta charset="utf-8">
 </head>
 <body>

    <form id="forma" action="#" method="post">
<div class="div">
  <button type="button" id="add">Добавить поле</button>
  <button>Отправить</button>
</div>
    </form>


    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script>
   		<script>
   	
   	$(document).ready(function() {

   		current = 1;

   		$("#add").click(function() {
   		current++;


   		$("#forma").append("<div class='div'>Поле:<input type='text' id='input' size='10' name='avon' value=''></div>");


   		var avon = $("#input").attr("name");
   		var avon_current = avon + current;
   		$("#input").attr("name", avon_current); 

   		var id = $("#input").attr("id");
   		var idkod_current = id + current; 
   		$("#input").attr("id", idkod_current); 


   		});
   	});

   </script>

   <?php
    	         echo @$_POST["avon2"] . "<br>";
   		 echo @$_POST["avon3"] . "<br>";
   		 echo @$_POST["avon4"] . "<br>";
    ?>

 </body> 
</html>

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1 answer(s)

D

Dmitry, 2016-08-05
@1bubaleh

Good evening.
Try sending data via ajax, do not clear the form after submitting or write it to cookies/session, clone the field when adding clone or substitute the value from cookies/session