How to get rid of invalid type argument of unary (have) error in C?

Question

C++ / C#

I wrote the code, it seems to be correct, but I got errors from which I can’t get rid of even looking at the answers on foreign forums. Pasted the whole code. I write in Atom, I compile via gcc
Here is what the compiler produces:

spoiler

C:\Users\Firetheestle\YandexDisk\ТТИТ\Labs>gcc Kimlaba7.c -o Kimlaba7.exe
Kimlaba7.c: В функции :
Kimlaba7.c:20:23: ошибка: invalid type argument of unary <*> (have )
printf("%2d \n",*(X+i*4+j));
^
Kimlaba7.c: В функции :
Kimlaba7.c:31:19: ошибка: invalid type argument of unary <*> (have )
int i=0,j=0,max=*(X+i*4+j),maxj=0;;
^
Kimlaba7.c:34:14: ошибка: invalid type argument of unary <*> (have )
if(max>*(X+i*4+j)){
^
Kimlaba7.c:35:13: ошибка: invalid type argument of unary <*> (have )
max=*(X+i*4+j);
^
Kimlaba7.c:39:5: ошибка: invalid type argument of unary <*> (have )
*(X+i*4+max)=0;
^
Kimlaba7.c: В функции :
Kimlaba7.c:45:8: предупреждение: при передаче аргумента 1 указатель преобразуется в целое без приведения типа
VVOD(A);
^
Kimlaba7.c:6:5: замечание: expected but argument is of type
int VVOD(int X){
^
Kimlaba7.c:46:9: предупреждение: при передаче аргумента 1 указатель преобразуется в целое без приведения типа
VIVOD(A);
^
Kimlaba7.c:15:5: замечание: expected but argument is of type
int VIVOD(int X){
^
Kimlaba7.c:47:15: предупреждение: при передаче аргумента 1 указатель преобразуется в целое без приведения типа
MAXANDOBMEN(A);
^
Kimlaba7.c:30:5: замечание: expected but argument is of type
int MAXANDOBMEN(int X){

I compile with the command:
gcc Kimlaba7.c -o Kimlaba7.exe
And here is the code itself:

/*
Дана матрица В(8,8). Заменить в каждой строке  матрицы
      максимальный элемент нулем.
*/
#include<stdio.h>
int VVOD(int X){
  int i,j;
  printf("Vvedite massive:\n");
  for(i=0;i<4;i++){
    for(j=0;j<4;j++){
      scanf("%d",X+i*4+j );
    }
  }
}
int VIVOD(int X){
  int i,j,k=0;
  printf("Vivod massiva \n");
  for(i=0;i<4;i++){
    for(j=0;j<4;j++){
      printf("%2d \n",*(X+i*4+j));
      k++;
      if(k==4){
        printf("\n");
        k=0;
      }

    }
  }
}
int MAXANDOBMEN(int X){
  int i=0,j=0,max=*(X+i*4+j),maxj=0;;
  for(i=0;i<4;i++){
    for(j=0;j<4;j++){
      if(max>*(X+i*4+j)){
        max=*(X+i*4+j);
        maxj=j;
      }
    }
    *(X+i*4+max)=0;
  }

}
int main(){
  int A[4][4];
  VVOD(A);
  VIVOD(A);
  MAXANDOBMEN(A);
}

Please help me figure it out ;z
THE PROBLEM IS SOLVED HERE IS THE WORKING CODE:

/*
Дана матрица В(8,8). Заменить в каждой строке  матрицы
      максимальный элемент нулем.
*/
#include<stdio.h>
int VVOD(int* X){
  int i,j;
  printf("Vvedite massive:\n");
  for(i=0;i<4;i++){
    for(j=0;j<4;j++){
      scanf("%d", X+i*4+j );
    }
  }
}
int VIVOD(int* X){
  int i,j,k = 0;
  printf("Vivod massiva \n");
  for(i=0; i < 4; i++){
    for(j=0; j < 4; j++){
      printf("%3d", *(X+i*4+j));
      k++;
      if(k == 4){
        printf("\n");
        k = 0;
      }

    }
  }
}
int MAXANDOBMEN(int* X){
  int i = 0, j = 0, k = 0,max = 0, maxj = 0;
  for(i = 0; i < 4; i++){
    max = *(X+i*4+j);
    for(j = 0; j < 4; j++){
      if(max < *(X+i*4+j)){
        max = *(X+i*4+j);
        maxj = j;
      }
    }
    j=0;
    *(X+i*4+maxj) = 0;
}

}
int main(){
  int A[4][4];
  VVOD(*A);
  VIVOD(*A);
  MAXANDOBMEN(*A);
  VIVOD(*A);
}

Answer 1

Read , (Don't be afraid of the C++ in the article's title, the only difference is how it prints to the screen). Now you are doing something strange. You declared the parameters as int, not *int.
PS I recommend immediately abandoning the caps in the names of functions, as it is customary to call constants. Transliteration is also not desirable, use a translator and learn English. After "," a space is placed. Before and before +-= etc. spaces are also customary.

Answer 2

so it is written
*(X+i*4+max)=0;
you can't do that
X+i*4+max is not a pointer
In VVod it's not at all clear what was passed.
You would be defined, with pointers, links or with what you work. Porridge