How to get a link and display it?

Question

PHP

Hello, guys, tell me examples of how you can bring this idea to life?
In general, I have a website with a video player, when I start the video, when I click on the play button, the video is downloading, i.e. in the developer console in the Network tab, there are requests with a response code 200 status, I need to catch this link and display a simple alert for example ( ); I found how to find out the response code from the link,
but then I can’t figure out how to do it.

$url = 'ссылка';
$ch = curl_init($url);
curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch,CURLOPT_TIMEOUT,10);
$output = curl_exec($ch);
$httpcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);

echo $httpcode;

it is necessary to display the link that comes from the server when you click on the play button

Answer 1

var href = $('a').attr('href');

Answer 2

If I understood correctly what you want, that is, ready-made plugins like "video download helper".
If not correct, then describe how the server with its curl should know from where you clicked play somewhere in your browser.