How to form an architecture in a framework?

M

ms23452015-12-28 18:42:04

CodeIgniter

ms2345, 2015-12-28 18:42:04

Hello. Let's say that I decided to make a site on the MVC type framework.
There is a controller: posts , view: posts_view , module: posts_model
There is a controller: users , view: users_view , module: users_model
I write all html code in files: posts_view and users_view .
Question: how would it be possible to implement the loading of the same container <head>and generally competently place all this in the tag <html>, and the contents of the views in <body>.
i.e.

<html>
   <head>
      //Тут подключаются все нужные мне front-end файлы и выводятся заголовок, мета-теги
   </head>
   <body>
      //Тут я могу подключать виды posts_view или users_view
   </body>
</html>

If I didn't explain it quite clearly - then at least tell me, please, where can I download or view a simple site implemented on a framework (MVC).

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2 answer(s)

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Stanislav Pochepko, 2015-12-28
@DJZT

ms2345 : did this on CI. <?php $this->view->load('header');?> If I'm not mistaken. And you can't send anything there. But the main thing in the main view in which you call is a string pass the necessary data for output

A

AAAA, 2016-01-14
@AlexanderWalker

And it's better to take this code to a separate library and call the function passing parameters to it

$headData['title'] = "";
$headData['keywords'] = "";
$headData['seo_description'] = "";
$headData['scripts'] = array(); // Массив скриптов. Потом во фронте циклом их выгрузить
$headData['styles'] = array(); // Массив стилей. Аналогично выгружать

$data['header'] =  $this->CI->load->view('template/header' , $headData , true); //Шапка
$data['footer'] =  $this->CI->load->view('template/footer' , array() , true); //Футер
$pageData['pageContent'] = array(); // Какой-то контент для страницы
$data['content'] = $this->CI->load->view('front/*your-page*' , $pageData , true); //Страницу которую грузить в шаблон
$this->load->view('template/'.$template , $data  ); //В какой шаблон грузить страницу