How to find the nth digit of a decimal number?

Question

C++ / C#

How to find the nth digit of a decimal number?

Answer 1

f(N, m) = (N div 10^(m-1)) mod 10
div - integer division
mod - taking remainder
N - number
m - digit number
ae:
N = 1324
m = 3
1324 / 100 = 13
13% 10 = 3

Answer 2

#include <stdio.h>

int digit(int number, int n) {
  if (n <= 1) {
    return number % 10;
  }
  return digit(number / 10, n - 1);
}

int main(void) {
  printf("%i\n", digit(12345, 1));
  printf("%i\n", digit(12345, 2));
  printf("%i\n", digit(12345, 3));
  printf("%i\n", digit(12345, 4));
  return 0;
}

https://ideone.com/ZSHndh

Answer 3

You can, as an option, translate the number into a string and take the nth index

Answer 4

you take the remainder of dividing by 10 - you get the last digit, then you divide the number by 10, removing the last digit. And so on until you reach the desired