How to find palindromes in a string?

Question

C++ / C#

I can't solve this problem in C:

Given a character string in which the words are listed separated by semicolons, and the total length is < 80. Find and print all words that are a palindrome word.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void polydrome(char **word){
    int x;
    int y;
    int lenth = strlen(word);
    for(x = 0, y = lenth-1 ; x < y; x++, y--){
        if(word[x] != word[y]){
            return;
        }
    }
    printf("\n%s",word);
}

int main() {

    //Инициализация переменных
    char line[80] = "";
    char **words[80];
    int count = 0;
    FILE *input;

    //Проверка открытия файлов
    if((input=fopen("/Users/nilinadvlr/Desktop/lab5/lab5/line.txt","r"))==NULL){
        printf("Файл не открылся\n");
        exit(1);
    }

    //Вывод всех данных
    fscanf(input, "%s", line);
    printf ("Исходная строка: %s\n", line);

    //Разделение на отдельные слова и вывод
    printf ("Результат разбивания:\n");
    words[count] = strtok(line, ";");
    while (words[count] != NULL){
        printf("%s\n", words[count]);
        count++;
        words[count] = strtok(NULL, ";");
    }

    //Вывод слов-полидромов
    printf("Слова-полидромы: \n");
    for(int i = 0; i < count; i++){
        polydrome(words[i]);
    }
}

Answer 1

Have you tried reading compiler errors and warnings?
void polydrome(char **word){-> void polydrome(char *word){
char **words[80];->char *words[80];

Answer 2

The problem is that word is an array of double pointers (**). Whereas strtok returns a normal pointer.
Because of this, here
if(word[x] != word[y])
you are comparing 2 pointers, not 2 characters.
In general, I would remove the word array in principle. You can immediately call polyndrome after you have found the next word.