How to find lines containing url using regular expressions in linux?

Question

linux

How to find lines containing url using regular expressions in linux?
With the grep command
I tried like this grep "[http\:]\+[a-zA-z0-9]+\.[az]\{2,4\}" /etc/
writes the wrong range

Answer 1

grep -rE 'https?://[a-zA-Z0-9][\.a-zA-Z0-9-]{1,61}[a-zA-Z0-9]\.[a-zA-Z]{2,}' /etc

Answer 2

urlregex.com
learn to ask the right questions to Yandex

Answer 3

Of course, incorrect - it should be like this:[a-zA-Z0-9]

Answer 4

Well, for starters - this pattern cannot be enclosed in double quotes, apostrophes are needed here - because quotes do not escape backslashes.
Then the entry "[http\:]" raises suspicion - probably, the whole string "http" is needed here, and not "any of the letters".
About "Az" they said here.
"/etc/" is a search in the body of the directory, i.e. among filenames (rather than in file bodies).