How to exclude gulp folder by pattern?

Question

JavaScript

it is not possible to exclude folders when processing gulp'om
as it is correct?
this option doesn't work

gulp.src(['!../folder/*.ru/js/*.js', '!../folder/*.com/js/*.js',  '../folder/**/js/*.js'])

you need to exclude the processing of folders with the ending .ru and the ending .com

Answer 1

In order to exclude a folder by a pattern, you must also specify an internal continuation, as is done for regular folders.

'!folder/*.ru/**/test.js',
'!folder/*.com/**/test.js',

Answer 2

Maybe put an exception at the end

gulp.src([
'../folder/**/js/*.js',
'!../folder/*.ru/js/*.js', 
'!../folder/*.com/js/*.js'
])

Answer 3

Exceptions are recommended to be set first.
Specify the exclusion path from the nesting level of the Gulp file.
That is, if you, for example, have gulpfile at the root, and the project itself is nearby in the app folder, then write:
'!app/js/*.js'