How to download video from VK using PHP?

Question

PHP

I made this parser:

$url = 'Ссылка на видео'; // https://vk.com/video-***_***

// 1080p
$re = '/"url1080":"(.*)"/U';
$str = getHTML($url);
preg_match_all($re, $str, $url1080, PREG_SET_ORDER, 0);

// 720p
$re = '/"url720":"(.*)"/U';
$str = getHTML($url);
preg_match_all($re, $str, $url720, PREG_SET_ORDER, 0);

// 480p
$re = '/"url480":"(.*)"/U';
$str = getHTML($url);
preg_match_all($re, $str, $url480, PREG_SET_ORDER, 0);

// 360p
$re = '/"url360":"(.*)"/U';
$str = getHTML($url);
preg_match_all($re, $str, $url360, PREG_SET_ORDER, 0);

// 240p
$re = '/"url240":"(.*)"/U';
$str = getHTML($url);
preg_match_all($re, $str, $url240, PREG_SET_ORDER, 0);

if(isset($url1080[0][1])) {
    $link = $url1080[0][1];
} elseif(isset($url720[0][1])) {
    $link = $url720[0][1];
} elseif(isset($url480[0][1])) {
    $link = $url480[0][1];
} elseif(isset($url360[0][1])) {
    $link = $url360[0][1];
} elseif(isset($url240[0][1])) {
    $link = $url240[0][1];
}

// Создаем Json (мне нужно для своего API)
$json = '{"url":"'.$link.'"}';
$json_d = json_decode($json);
$link = $json_d->url;

$filename = uniqid();

// Скачивание видео на сервер
copy($link, "../../../api/v2/method/" . $filename . ".mp4");

// Смотрим код страницы
function getHTML($url) {
    
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/98.0.4758.102 Safari/537.36');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, false);
curl_setopt($ch, CURLOPT_HEADER, [
    'Accept-Language: ru'
]);

$html = curl_exec($ch);
curl_close($ch);

return $html;
}

I get a link to an mp4 file successfully, but it won't download. Since they have a link tied to an ip address. Sometimes, upon opening the link, it immediately downloads in the browser, sometimes not. What can be done?

Answer 1

Found a way. You need to download the video also via Curl

// Функция загрузки видео
function videoDownload($url) {
$filename = uniqid();
$fp = fopen($filename . ".mp4", 'w'); // Путь скачивания
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/98.0.4758.102 Safari/537.36'); // Обязательный параметр, без него не скачивается
curl_setopt($ch, CURLOPT_FILE, $fp);
$data = curl_exec($ch);
curl_close($ch);
fclose($fp);
}

Answer 2

but it doesn't download.

When something does not work, errors usually occur, including errors that can be forwarded from the api side, and sometimes they are even clearly described. See the contents of the response returned from the server, including the server response code.

Answer 3

You also need to specify cookies. They are not in the code.