How to do substitution in bash?

Question

bash

There are two text files that contain let.

Содержимое первого
/test1/file 1.txt
/test1/file 2.txt
/test1/file 3.txt
Содержимое второго
/test2/papka 1
/test2/papka 2
/test2/papka 3

I use this script

#!/bin/bash
a=$(cat text01.txt)
b=$(cat text02.txt)
VAR=$(paste -d " " <(echo "$a") <(echo "$b"))
echo "$VAR"

Получается
/test1/file 1.txt /test2/papka 1
/test1/file 2.txt /test2/papka 2
/test1/file 3.txt /test2/papka 3

How now to substitute each line in the mv move command?

Answer 1

Are you sure there are spaces in the filenames?
If not, then you can do this:
or this

sed "s/.*/mv /" 1.txt >text03.txt
paste text03.txt text02.txt text01.txt

If there are, they must first be shielded.

sed -i "s/ /\\\ /g" text01.txt text02.txt
paste 1.txt 2.txt|xargs -n2 mv

Answer 2

`mv $VAR`
string at the top in backticks

Answer 3

a=$(cat text01.txt)
b=$(cat text02.txt)
VAR=$(paste -d "\n" <(echo "$a") <(echo "$b"))

xargs -d "\n" -n 2 mv <<< "$VAR"

while read -r file
do
    files[$((i++))]="$file"
done < text01.txt

while read -r dir
do
    mv "${files[$((j++))]}" "$dir"
done < text02.txt