How to display all words of a string containing an odd number of letters relative to the center of the word?

Question

Python

Task: given a string of characters consisting of individual words separated by a space. Output all words of a string containing an odd number of letters relative to the center of the word. All that I could write (still with an error):

a = input("Enter symbols: ").split()
b = []
for i in a:
    if (len(a[i])) %2 != 0:
        b.append(i)
print(b)

Answer 1

for i in a:
If you apply the for statement to a list, it enumerates the elements of the list, not the indices.
So not len(a[i]) but len(i)