How to determine the variable name passed to min(), max() in python?

Question

Python

Hello!

There are variables:
a = 0
b = 1
c = 2
d = 3

all = min(a, b, c, d)
print all
###############
output 0

How can I understand now that 0 is a variable named a?

Answer 1

You don't need it. You are working with data, not variable names.
Game, but this is "what you need":

a = 0
b = 1
c = 2
d = 3

alls = min(a, b, c, d)

globs = globals().copy()
for i in globs:
  if id(globs[i]) == id(alls):
    print("имя переменной, у которой самый маленький int:", i)
    break

all is a reserved name, don't use it.

Answer 2

d={'a':0, 'b':1, 'c':2, 'd':3}
print(min(d, key=d.get))

Answer 3

min , max , and others only return the minimum value, not the name of the variable with the minimum.
You can simply define your own variable denoting the minimum number
min_num = min(a,b,c,d)

Answer 4

---------------------------------
Caution! Shitcode!
---------------------------------

l = locals()

print([i for i in l if l[i] == 0][0])

Answer 5

So far, nothing has come up, the task is to calculate the minimum number among 4 variables and then use this variable in the code.