How to count the percentage of elements in a list with LINQ?

Question

C++ / C#

Tell me how you can calculate the percentage using LINQ and display its result?
There is a list of values, it can be different in number. It is necessary to display, for example, 30 percent of this list, that is, [9,8,7] (33%). Rounding up.

public void Start()
{
    var list = new List<int> { 1, 2, 3, 4, 5, 6, 7, 8, 9 };
    list.Top(30)
}

public void Top(int list)
{
    IEnumerable<int> topPercent = ;
}

It must also be limited by the number of elements in the output collection. Maximum 100, otherwise throws an exception.

Answer 1

list.Take(list.Count() * 30 / 100)
I think with a check for 100 and an exception you will figure it out yourself.