How to count the number of delimiters in a string?

Question

cmd/bat

There is a line
значение1^значение2^значение3^
How to count the number of delimiters?

Answer 1

The cap symbol ^is "special" to cmd. So it should not be used as a separator if you plan to solve the problem on batch files.
In general, your problem can be solved like this:

@echo off

set "str=hjh#jhjh#hkjh#khkjh##khkjh"
set "delim=#"
set "count=0"

:loop
call:finddelims
if defined str goto:loop
echo.%count%
goto:eof

:finddelims
for /f "tokens=1,* delims=%delim%" %%a in ("%str%") do (
  echo.%%a
  set /a "count+=1"
  set "str=%%b"
)

Here I chose the symbol # as a separator, the string was set in the variable str with an arbitrary string with separators.
The double delimiter counts as 1. The delimiter at the end of the line is ignored.