How to correctly pass the password and login to the bash script as an argument?

Question

linux

How to correctly pass the password and login to the bash script as an argument?
For example, to connect to a database

Answer 1

If this is access to the site database, then parse from its own files. For example, here is Bitrix:

#!/bin/sh
doc_root=~/public_html
dbconn=$doc_root/bitrix/php_interface/dbconn.php

host=`cat $dbconn | grep DBHost | sed 's/.*"\(.*\)".*/\1/'`
username=`cat $dbconn | grep DBLogin | sed 's/.*"\(.*\)".*/\1/'`
password=`cat $dbconn | grep DBPassword | sed 's/.*"\(.*\)".*/\1/'`
database=`cat $dbconn | grep DBName | sed 's/.*"\(.*\)".*/\1/'`

Answer 2

#!/bin/bash
echo $0
echo $1
echo $2
echo $3

We start
./myscript 5 10 15
Output

more options here
https://habr.com/ru/company/ruvds/blog/326328/