How to correctly issue an ajax request and display the result?

Question

PHP

I am writing a parser that parses various information (pictures, text, fields, files). The first screen looks like just an input with a link pasted and a parse button.
When a button is clicked, I use ajax to send a request to the parse.php php file, which goes through the page and subpages and collects information.
The idea is this - when you click on the button, so that there would be no page reload - I just display: none forms and buttons, and then I need to load information according to the template (there is one template for pictures, another for fields and depends on the conditions).
How to do it more competently for further expansion of logic?
1. sew the parsing layout into the php file parse.php itself and get ajax html response?
2. sew layout into javascript?
3. how is it different?

Answer 1

Depends on how you are going to work with the received data in the browser.