How to convert browser-sync command to gulp?

Question

JavaScript

Now I use this command
browser-sync start --proxy="localhost:80" --files="*.html, *.css , *.php"
it spawns my php server and monitors html css and php files, but I you also need to process sass files, and it's better to do it in a gallop.
How to convert this command into a gulp task?

Answer 1

add a sass processing task to dependency so that before launching the browser it will convert your sass to css