How to convert an unsigned number to 4 bytes?

Question

Programming

The essence of the problem is that this must be done without the use of shifts and bitwise operations. I managed to quickly find an algorithm for converting a number into 2 bytes.

word x=8800; // = 0x2260

byte a=x/256;
byte b=x%256;

It seems to me that here you need to somehow use the value 16 777 216 for high bytes.

Answer 1

That's why institute education (programmer) is useless, because they force you to use division where you need to use shifts and binary operations.
On the subject, you think correctly:
low byte = x% 256
first byte = (x / 256)% 256
second byte = (x / (256 * 256))% 256
high byte = x / (256 * 256 * 256)

Answer 2

What language is it?
For C/C++

long val = 0x12345678;
printf("long: %ld\n", val);
printf("short: %d %d\n", ((short *)(&val))[0], ((short *)(&val))[1]);
printf("char: %d %d %d %d\n", ((char *)(&val))[0], ((char *)(&val))[1], ((char *)(&val))[2], ((char *)(&val))[3]);

or via union

union {
    long l;
    short s[2];
    char c[4];
} val;
long val.l = 0x12345678;
printf("long: %ld\n", val.l);
printf("short: %d %d\n", val.s[0], val.s[1]);
printf("char: %d %d %d %d\n", val.c[0], val.c[1], val.c[2], val.c[3]);

Answer 3

C:
val = 0x1234;
a = (val & 0xFF);
b = (val >> 8);
Oops!