How to connect gulp-watch?

Question

JavaScript

Good afternoon!
Can you tell me how to properly connect and start tracking for css & js files?
tasks:

const watch = require('gulp-watch');

 gulp.task('cssc', () => {
    return gulp.src('./build/scss/*.css')
        .pipe(sourcemaps.init())
        .pipe(csscomb())
        .pipe(mmq({
            log: true
        }))
        .pipe(cleanCSS())
        .pipe(rename({
            suffix: ".min"
        }))
        .pipe(sourcemaps.write())
        .pipe(gulp.dest('./css/'))
});

gulp.task('jsc', () => {
    return gulp.src(['bodyload.js', 'toggle.js'].map(file => `./build/js/${file}`))
        .pipe(sourcemaps.init())
        .pipe(babel({
            presets: ['@babel/preset-env']
        }))
        .pipe(concat('scripts.js'))
        .pipe(uglify())
        .pipe(rename("scripts.min.js"))
        .pipe(sourcemaps.write('.'))
        .pipe(gulp.dest('./js/'))
});

gulp.task('watch', function() {
    gulp.watch('./build/scss/*.css', ['cssc']);
    gulp.watch('./build/js/*.js', ['jsc']);
  });

does not work

Answer 1

https://www.youtube.com/watch?v=r2S423N-ETA I didn’t see this lesson better on youtube at all

Answer 2

Make a task
clean - cleaned build, build - collected, watch - put on observation

Answer 3

Hello, most likely you are using the 4th gulp, where the task call is implemented differently.
Instead of an array, a function is passed as the second argument, either gulp.series or gulp.parralel. In arguments, you pass the names of tasks without any arrays (gulp.series("task", "task")).
PS Put semicolons after the last pipes.