How to compare dates in BASH?

Question

bash

There is a certain date: 2022-02-19 13:32:09
And there is a local date:
date +%Y-%m-%d\ %H:%M:%S

How to find out how many minutes have passed?

Answer 1

d=`date +%s -d '2022-02-19 13:32:09'`
echo $(( (`date +%s` - d) / 60 )) # количество минут от заданного до текущего времени

Answer 2

1. google how to convert a date to a unix timestamp in bash
2. (optional) google how to get the current unix timestamp
3. subtract one from the other, get the difference in seconds
4. how to get minutes from seconds, I really hope you can overpower yourself

Answer 3

Usually I don’t directly suggest the code, but here everything is as simple as a log:

_newcrl=`date -r $file1 +%s`
_oldcrl=`date -r $file2 +%s`

if [ $_newcrl -gt $_oldcrl ]; then
# тут делаем чегой-то
fi