How to check if there are letters and NUMBERS ¹ ² ³ ⁴ ⁵ ⁶ ⁷ ⁸ ⁹ ⁰ in a variable?

Question

Python

a = str(input('> > > '))
if True:
    for x in a:
        
        if x.isdigit() == True:
            #хабр не распознает некоторые из эти цифр
            if x == '¹' or x == '²' or x == '³' or x == '⁴' or x == '⁵' or x == '⁶' or x == '⁷' or x == '⁸' or x == '⁹' or x == '⁰':
                
                print(False)

            else:
                
                age = int(age)
                if age <= 18 or age >= 100:
                    print(False)
                else:
                    age = str(age)
                    print(True)
                    # КОД ...
        else:
            
            print(False)

The age variable must contain only numbers. This is done by isdigit() , but it also accepts this: ¹ ² ³ ⁴ ⁵ ⁶ ⁷ ⁸ ⁹ ⁰ digits, so it outputs True if there are any in the variable. With the help of the code, I can check each character and sort it through if else . But I need the code to check each character, and only after that, depending on whether it contains letters or ¹²³⁴⁵⁶⁷⁸⁹⁰ , executes a certain code. You cannot use global variables. And apparently you need to do it all in one function.

Answer 1

link there are many examples

try:
    val = int(userInput)
except ValueError:
    print("That's not an int!")