How to check if an element exists on a page using python+selenium?

Question

linux

I go to a page where there can be either a sign with different options or an input field and a confirm button. If there is no input field - I want to be able not to run into a traceback that they say

selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element:

.
for this I thought to use try, except. They say
try:
browser.find_element_by_name('') ​​#they found the input field, entered what they wanted, confirmed with the button and that's all and got their plate with options; or if there is no input field, but there is a plate with options right away - look for what I need.
except selenium.common.exceptions.NoSuchElementException: #on except I tried to catch this piece, but apparently it's not possible. It is not described in the exceptions ... How to be?
Who has already run into similar moments when I assume that there is no element and just want to perform ANOTHER action if there is no element, and not fall into traceback.

Answer 1

from selenium.common.exceptions import NoSuchElementException
try:
do something with the element
except NoSuchElementException:
do something else
This scheme works for me.