How to check by key?

Question

PHP

Good afternoon, there is such an array in php

array(2) {
  [0]=>
  array(4) {
    ["category_id"]=>
    string(3) "137"
    ["name"]=>
    string(49) "Лента термоуплотнительная"
    ["children"]=>
    array(0) {
    }
    ["href"]=>
    string(90) "http://site/index.php?route=product/category&path=1_134_135_136_137"
  }
  [1]=>
  array(4) {
    ["category_id"]=>
    string(3) "138"
    ["name"]=>
    string(89) "Огнезащита для воздуховодов с применением матов"
    ["children"]=>
    array(0) {
    }
    ["href"]=>
    string(90) "http://site.ru/index.php?route=product/category&path=1_134_135_136_138"
  }
}

Each array is another array with keys. The array itself above is in a variable. The question is, how can I check that if at least one element of the children array is not empty, then execute one function. That is, in the example above, children are empty everywhere, but if at least somewhere there is ['children'] =>array (1) then fulfill the conditions. Thanks in advance

Answer 1

$array = [/* ... */];

if (arrHasChildren($array)) {
    // doSomeThing();
}

function arrHasChildren(array $array): bool
{
    foreach ($array as $value) {
        if (!empty($value['children'])) {
            return true;
        }
    }

    return false;
}

Answer 2

Offhand, something like this:

function array_any(array $array, callable $fn) {
    foreach ($array as $value) {
        if($fn($value)) {
            return true;
        }
    }
    return false;
}

array_any($arr, function ($i) { return !empty($i['children']) }) // true || false