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Alexus50002020-05-22 18:28:22
Arduino
Alexus5000, 2020-05-22 18:28:22

How to calculate the power consumption and power of the device on Arduino?

I am developing autonomous scales for hives with wireless data transmission. For the weighing platform, I took the Arduino UNO as a basis; an HX711 ADC with tenac sensors, a CMA noise sensor and an MCP temperature sensor, and an NRF radio module are connected to it. The Arduino UNO is powered by a 3.7V battery through a 5V converter and a solar module. The data will be transmitted to the arduino nano and then through the gsm module via sms. An Ai-Thinker A6 GSM module and an NFR24L0 radio module are connected to the Arduino Nano. It is powered by a 3.7V battery with a converter up to 5V and a solar battery. How to calculate how much current the system will consume and how much power it will produce? And how long will batteries last with such a design how to calculate? Maybe you will have more effective suggestions? It is desirable to describe in detail the formulas for the calculation. I will be grateful!

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VT100, 2020-05-25
@Alexus5000

It is possible to provide a jumper in the power circuit of each of the devices for connecting an ammeter and edit the software by observing the current consumption, as in the Apollo 13 movie. You just need to remember that not every device will be able to show, for example, GSM-burst.
But, since for adequate editing you still need to study the documentation, you can start with it ... Consumption currents in standby modes will give the upper limit of the system's quiescent current. In operating modes - typical current consumption. Next - integrate these currents over a long period. For example, for an hour, the standby state will be 50 minutes, idle operation 9 minutes, and data transmission 1 minute. Average current = (I1*50+I2*9+I3)/60. And do not forget to recalculate the currents of DC / DC converters through the output and input power (according to voltage changes) and typical efficiency.

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Vladimir Korotenko, 2020-05-22
@firedragon

https://habr.com/en/post/444326/

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