How to break a promise chain without throwing an error?

Question

JavaScript

How to make it so that if one worked return res.json(), then the next one was no longer executed? Not using nesting.

newArticle
    .save()
    .then(article => {
      Section
        .findOneAndUpdate({ _id: article.section }, {$push: {"articles": article._id}}, {new: true})
        .then(section => {
          if (section === null) return res.json({ message: 'No sections found' })
        })
        .catch((err) => {
          return next(err)
        })
      return article
    })
    .then(article => {
      return res.status(201).json({
        status: 'OK',
        article
      })
    })
    .catch(err => {
      return next(err)
    })

Now if it works

if (section === null) return res.json({ message: 'No sections found' })

then the headers are sent twice and the server swears.

Answer 1

Async / await is possible?

async (req, res) => {
...
try { 
    let article = await newArticle.save();
    let section = await Section.findOneAndUpdate({ _id: article.section }, {$push: {"articles": article._id}}, {new: true});
    if (section === null) return res.json({ message: 'No sections found' });

    res.status(201).json({
        status: 'OK',
        article
    });
}
catch(e) {
    console.log(e);
    next(e);
}