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Valentine2017-09-10 16:39:17
Python
Valentine, 2017-09-10 16:39:17

How to beautifully print a quadratic equation to the console?

Wrote a simple code for solving quadratic equations. In the end, I decided to write the output of the final equation on the screen as a final touch before starting the solution, after a few minutes I realized that I did not understand how to implement it. First, the quadratic equation can be like this 2x^2+5x-4 or like this -2.1x^2-4.5x+8.3 (numbers in front of x can be both negative and positive, as well as fractional or integer). So, briefly the question is: how to make the output flexible and beautiful? I do not want to see, when entering only integer values, something like 2.0x^2+5.0x-4.0 = 0 and so on. Spoiler code.

The code
import math

while True:
    a = float(input('Введите a: '))
    b = float(input('Введите b: '))
    c = float(input('Введите c: '))

    d = b ** 2 - 4 * a * c
    print("\nВычисляем дискриминант...")
    print("Дискриминант равняется", d)

    if d == 0:
        print("\nДискриминант равен 0")
        print("x =", -b/(2*a))
    elif d < 0:
        print("\nДискриминант меньше 0, решений нет")
    else:
        x1 = (-b - math.sqrt(d)) / (2*a)
        x2 = (-b + math.sqrt(d)) / (2*a)
        print("\nВычисляем корни...")

        print("\nПервый корень равен", x1)
        print("Второй корень равен", x2)

    while True:

        print("\nХотите решить ещё одно уравнение?")
        answer = input('Y/n(help - справка по командам) ')

        if answer == 'Y':
            break
        elif answer == 'n':
            exit()
        elif answer == 'help':
            print(open('help.txt', 'r').read())
        else:
            print("\nВведите Y или n (help - справка по командам)")

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1 answer(s)
J
javedimka, 2017-09-10
@val_gr

If you want to leave forced formatting in float, then you can do this:

def quadratic_eq_formatter(nums):
    num_f = {1: '{:+.0f}', 0: '{:+.1f}'}
    eq = '{}x^2{}x{}=0'.format(*(num_f[x.is_integer()] for x in nums))
    return eq.format(*nums) if nums[0] < 0 else eq.format(*nums)[1:]

nums = (a, b, c)
print(quadratic_eq_formatter(nums))

print(quadratic_eq_formatter([-3.0, -2.7, 7.0]))
'-3x^2-2.7x+7=0'
print(quadratic_eq_formatter([2.0, 5.0, -4.0]))
'2x^2+5x-4=0'
print(quadratic_eq_formatter([-2.1, -4.5, 8.3]))
'-2.1x^2-4.5x+8.3=0'

And in order to be beautiful in general, then ^ 2 in
can be changed to
then it will be something like:
print(quadratic_eq_formatter([-2.0, 5.0, 5.2]))
-2x²+5x+5.2=0

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