How does this definition of a private address work in Python?

Question

Python

Source: https://stackoverflow.com/a/28950776
Code

import socket
def get_ip():
    s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    try:
        # doesn't even have to be reachable
        s.connect(('10.255.255.255', 1))
        IP = s.getsockname()[0]
    except Exception:
        IP = '127.0.0.1'
    finally:
        s.close()
    return IP

Moreover, here there is an appeal to the network 10.х.х.х.х - to its border, while in the code I get my gray ip with NAT-a - in the range 192.168.х.х. How it works?

Answer 1

As I understand it, it doesn't matter what the address is - all the magic is in getsockname, and the address there can be any sane outside the computer. Although 8.8.8.8 is just for the socket to knock outside the computer.