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How does Jmp (E9) work at the opcode level?
Hello hacker.
I can't figure out the addressing of jmp in x86 asm .
Specifically, there is a section of machine code:
Which redirects control to the address: 0x03440000
After which the reverse addressing occurs: I can’t understand how 5EC8A902 and 03440000
are interconnected .
PS Maybe the question is stupid, because I did not climb into the jungle of machine code, but a cursory googling did not bring any results.
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For PIC, most transitions are relative transitions.
For absolute ones require changes after loading into memory at a certain address.
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