How does Django process requests?

Question

Django

https://djbook.ru/rel1.9/topics/http/urls.html#how...
Volume 4 definition:
If one of the regular expressions matches the URL, Django will import and call the corresponding view, which is just a function Python (or view-class). When called, the following arguments are passed:
and there are passed:
1) The HttpRequest object.
2) If the regular expression results in named matches, they will be passed as positional arguments.
3) Named arguments are created from named matches. They can be overwritten with values ​​from the kwargs argument passed to django.conf.urls.url().
And if I specify only one parameter in my view, then how will Django pass 2 and 3 arguments?
Example :

urls.py
from django.conf.urls import url
from . import views

urlpatterns = [
  url(r'^$', views.index, name ='index'),
]
view.py
from django.shortcuts import render
from django.http import HttpResponse
# Create your views here.

def index(request):
  return HttpResponse("Hello, world.")
вот тут я указываю что моя функция принимает только один параметр 
а остальные как будет получены?