How does bash keep its name when running a background task in a script?

Question

*nix-like systems

ls -Ra / &
kill -s TSTP $!
read

If you run the code below in bash as a *.sh file, and then run top, then instead of ls we will see the process as bash.
How does he do it and why?

Answer 1

$! = pid of the last process in the background
Well, kill either kills ls, or it's not clear at all, but not bash - because bash is not a background process here.