How does a function access itself when called recursively?

Question

JavaScript

Is it correct to say that when a function is called recursively in code, the js engine looks for the declaration of the called function in the outer scope? Below is the code with comments.

function func() {  //функция func объявлена в глобальном контексте
    func(); 
/*в текущей области видимости 'func' не объявлена, поэтому движок 
ищет объявление во внешней области видимости (в данном случае это
 глобальная область видимости), находит его там и теперь может выполнить функцию*/
}

Getting access to variables and functions occurs approximately as I described above (we immediately look inside the current scope, then we go in turn to look in external ones). Is this logic suitable for recursive calls, or do they follow their own "laws"?

Answer 1

Everything is correct https://jsfiddle.net/yy38x0mg/
This logic is valid for any calls.

Answer 2

In js, if something is not declared, it always looks in the outer scope.
You can read more here: https://learn.javascript.ru/closures

Answer 3

'func' is not declared in the current scope

just announced. In any named function, its name is created at the time of the call (along with arguments and this) and refers to the function itself. This is most clearly shown by named function expressions:

var f = function func() {
  console.log(func.name); // 'func'
};
console.log(f.name); // 'func'
console.log(func.name); // Reference error так как func нет в этой области видимости