How do I give 404 for existing links?

Question

Yii

A request of the form
/?r=blablaor any similar one /?mod=blabla
opens a page from 'defaultRoute' => 'site/default/index',
And I want it to give out 404.
How to do this?
Here is my wheel

'enablePrettyUrl' => true,
    'enableStrictParsing' => false,
    'showScriptName' => false,
    'rules' => [
        '<_m:[\w\-]+>/<_c:[\w\-]+>/<_a:[\w\-]+>' => '<_m>/<_c>/<_a>',
    ],

if 'enableStrictParsing' => false, turn to true then yes, but when opening a site without a request, i.e. site.ru opens a 404 error from

'errorHandler' => [
            'errorAction' => 'site/default/error',
        ],

defaultRoute stops working (
Tell me where is the error?

Answer 1

You can, for example, check for the existence of a GET parameter and issue a 404 error like this
throw new \yii\web\NotFoundHttpException();