How can I make two tasks run when a file is changed?

Question

gulp.js

Let's say there are two tasks, the first one compiles scss to css, and the second one beautifies the scss file itself, and I need these two tasks to work when the scss file changes. Here is the code to run the sass task, but the sass-beautify task must also run at the same time. How to do it?
gulp.watch("./scss/*.scss", gulp.series("sass"));

Answer 1

gulp.series(gulp.parallel('sass', 'sass-beautify')