How can I make sure that if the numbers in the interval were in the tuple a certain number of times, the condition is fulfilled?

Question

Python

Hello, there is a tuple with numbers

count = (5.60, 1.44, 1.32, 4.90, 2.97, 4.37, 7.18, 1.52, 1.20, 1.48, 1.45, 1.23, 3.58, 1.16, 0, 3.20, 3.36, 3.06, 12.78,
1.16, 1.17, 1.06, 1.23, 2.04, 5.21, 1.00, 1.32, 1.05, 5.33, 1.08, 4.29, 3.14, 1.04, 0, 1.22, 1.44, 1.00, 0, 1.55, 2.35,
1.98, 2.07, 1.82, 1.34, 4.12, 5.64, 1.16, 2.63, 1.97, 1.66, 2.70, 1.09, 24.37, 2.73, 1.30, 1.41, 1,103.24, 1.25, 0,
16.82, 1.03, 0, 1.20 ... )

I access numbers in the following way:

number = 1 # number for tuple
while True:
    if count[number] == 1.32:
        print('Игра 1.32 нашлась на месте ' + str(number))
        break
    else:
        number += 1

I define the gap like this:

kf_waits_ot =  1.32 # начало промужутка кф, от
kf_waits_do =  10  # окончание промежутка кф, до

It is necessary to make, for example, in the interval 1.30 - 5.00 the numbers were 3 times in a row, then this and that will be
done And I got something like this:

kf_waits_ot =  1.32 # начало промужутка кф, от
kf_waits_do =   1.45 # окончание промежутка кф, до
number_kf_waits = 2 # кол-во раз сколько числа из промежутка должны выпасть

while True:
  if count[number] >= kf_waits_ot and count[number] <= kf_waits_do:
    if number_kf_waits != number:
      number += 1
      print('False')
    else:
      print('True, bet allow')
      break
  else:
    number += 1
    print('Число не подходит в промежуток, следующее...')

This script somehow worked and found the interval, but if I enter larger numbers or longer intervals, then something strange happens and, according to the results of the script, I cannot find the interval that was considered correct.

Please help :)

Ps I didn’t even understand why the number of numbers in the interval should not be equal to the number for the tuple

Answer 1

kf_waits_ot =  1.32
kf_waits_do =   1.45
number_kf_waits = 2


numbers_in_row = 0
for number in count:
    
    if number >= kf_waits_ot and number <= kf_waits_do:
        numbers_in_row += 1
    else:
        numbers_in_row = 0
    
    if numbers_in_row == number_kf_waits:
        print('++')
        break