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Zend2011-12-22 15:24:27
Encryption
Zend, 2011-12-22 15:24:27

Help with Vigenère cipher

Comrades, help decipher the Vigenère cipher.

ESNRESYYOGUNHFFSCHBPKEPCCHTFFEURYASHFFZAKSHVSCHDWARFGSHYUYSHIOZHKUFBFAPSYOFGFG

It is known for sure that the key is 11 characters long. I used the frequency method with separate blocks, but the cipher does not lend itself.

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6 answer(s)
M
Mrrl, 2011-12-23
@Zend

Given that there are three errors in the phrase, it is very difficult to decipher it. But probably.
First, for each possible letter of the code, we calculate its probability (according to the frequency of the letters in the column). Sort the options by probability. Then we write out the 100,000 most probable rows (trivial dynamics). For each row, we calculate its probability according to the digraph frequency table. We sort. We look at the list for a long time. We assume that at the beginning the word "only". We select the lines starting with this word - there are only 86 of them. We choose the most meaningful. And manually edit two or three columns. 3 hours of work - and the answer is in your pocket. Almost half of the text is occupied by the signature :)

A
Alexander, 2011-12-22
@AlexRed

Probably someone has a test in cryptography on fire))

V
Vladimir Martyanov, 2011-12-22
@vilgeforce

Badly tried to do private analysis. Start with the letter O, for example ;-) I messed up somewhere, but the fragments “only”, “philosopher”, “demon”, “in my own” turned out quite well for me.

D
Denis, 2011-12-22
@uscr

Sorry for the offtopic, but is this a contest or from some site with such smart entertainment? If it's a website, can you share a link?
There is just a similar question on the mail replies:
http://otvet.mail.ru/question/68595812/

Z
Zend, 2011-12-23
@Zend

Meaningful fragments can be obtained at the beginning of the ciphertext or in the middle or somewhere else, but not the fact that the key is correct. Maybe the key was just successfully selected and the word turned out. The rest of the text is in the form of abracadabra, which means the key is not correct.

Z
Zend, 2011-12-23
@Zend

Thank you all!

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