Gulp userref, how to substitute a variable in the path to css / js files in the output html?

Question

gulp.js

I'll try to explain as simply as possible , namely visually
: And if so, how?

Answer 1

A crutch on a crutch and a crutch drives. But it works.
.pipe(replace(/css(\/[a-z0-9.\/]+\.(css))/gi, '$1'))
.pipe(replace(/(\/[a-z0-9 .\/]+\.(css))/gi, '<?php echo TEMPLATE_PATH ?>/css$1'))
.pipe(replace(/js(\/[a-z0-9.\/]+\ .(js))/gi, '$1'))
.pipe(replace(/(\/[a-z0-9.\/]+\.(js))/gi, '<?php echo TEMPLATE_PATH ?> /js$1'))
By the way, the problem is known.