gulp. The project is being built, but the build folder is empty. Why?

Question

JavaScript

Hello! I'm working on a new project, the assembler is Gulp. I ran into some incomprehensible problem that I had not encountered before - the project is being built (judging by the terminal in Webstorm), but the final folder with the built project remains empty. The rigger plugin is used to include html files. Below is the gulpfile code, so far it only contains a task for building html.

'use strict';

var gulp = require('gulp'),
    watch = require('gulp-watch'),
    prefixer = require('gulp-autoprefixer'),
    uglify = require('gulp-uglify'),
    sass = require('gulp-sass'),
    sourcemaps = require('gulp-sourcemaps'),
    rigger = require('gulp-rigger'),
    cssmin = require('gulp-minify-css'),
    imagemin = require('gulp-imagemin'),
    pngquant = require('imagemin-pngquant'),
    rimraf = require('rimraf'),
    browserSync = require("browser-sync"),
    reload = browserSync.reload;


var path = {
    build: {
        html: 'build/'
    },
    src: {
        html: 'src/*.html'

    },
    watch: {
        html: 'src/**/*.html'
    },
    clean: './build'
};

gulp.task('html:build', function () {
    gulp.src(path.src.html) //Выберем файлы по нужному пути
        .pipe(rigger()) //Прогоним через rigger
        .pipe(gulp.dest(path.build.html)) //Выплюнем их в папку build
        .pipe(reload({stream: true})); //И перезагрузим наш сервер для обновлений
});

The paths are correct. Attached is a screenshot of the project structure . Assembly is correct - screen .
What is wrong?

Answer 1

I did not see correctly prescribed paths, exceptpath.clean

Answer 2

Add return to the line
And yes, Denis Bukreev wrote you correctly, it is correct to specify the paths like this: ./build