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Pavel Gryaznov2021-01-19 19:10:12
go
Pavel Gryaznov, 2021-01-19 19:10:12

Golang how to elegantly parse time.Duration?

You need to parse string into time.Duration. Format "HH:MM:SS"

Go already has a very convenient parsing of dates, you can read the string through , but from further on you need to get . It seemed to me that there is another convenient method in the standard library . It would seem that this code should work:time.Parse("15:04:05", stringToParse)time.Duration{}time.Sub()


func parseDur(s string) time.Duration {
  t, _ := time.Parse("15:04:05", s)
  return t.Sub(time.Time{})
}


But this code returns time.Duration{}minus 1 year. You can fix it by returning it, but it looks so ugly. I mean, the zero time value in Go is but by default it returns . This looks strange. Is this some kind of design flaw and does it need to be fixed at the standard library level? The main question "how to parse elegantly" remains valid, maybe someone has some nice methods without strange constants. t.AddDate(1, 0, 0).Sub(time.Time{})

0001-01-01 00:00:00 +0000 UTCtime.Parse()
0000-01-01 00:00:00 +0000 UTC

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